.03x^2-x+100=93

Solution for .03x^2-x+100=93 equation:

.03x^2-x+100=93

We move all terms to the left:

.03x^2-x+100-(93)=0

We add all the numbers together, and all the variables

.03x^2-1x+7=0

a = .03; b = -1; c = +7;
Δ = b2-4ac
Δ = -12-4·.03·7
Δ = 0.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{0.16}}{2*.03}=\frac{1-\sqrt{0.16}}{0.06}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{0.16}}{2*.03}=\frac{1+\sqrt{0.16}}{0.06}
$